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Re: series capacicty
- To: tesla-at-pupman-dot-com
- Subject: Re: series capacicty
- From: Terry Fritz <twftesla-at-uswest-dot-net>
- Date: Fri, 28 Jul 2000 16:33:36 -0600
- Delivered-To: fixup-tesla-at-pupman-dot-com-at-fixme
- In-Reply-To: <00d801bff8a9$61985d40$d9fbfea9-at-jeroen>
Hi Jeroen,
At 05:02 PM 7/28/00 +0200, you wrote:
>
> Hi all,
>
> A while back I asked, that when I would put caps in series, that the voltage
> would be a total of the sum of all,
> and if the capacitance would be devided by the number of caps, the anser was
> no, the capacitance would stay the same, but my meter says different !
>
> in other words if i take 3 caps, each 3000 Volts, 3mF
> Than that would be a total of 9000Volts with 1mF ???? at least that is waht
> my meter says.
>
> but some say that it would make 9000 Volts with 3 mF ?
>
> so which one is it ??
>
> geetings from Jeroen Kooiman from the Netherlands (Holland)
The voltage is the SUM. So you would get 9000 volts total.
The capacitance would DIVIDE. So you would get 1mF.
When you start to have series and parrallel caps and of different values,
things can get a complicated.
Cheers,
Terry