Re: Voltage determination

["TruckDrivingMan" <Tom.Ansorg-at-t-online.de> (by way of Terry Fritz <twftesla-at-uswest-dot-net>)]

----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Friday, July 28, 2000 1:07 AM
Subject: Re: Voltage determination


> Original poster: Terry Fritz <twftesla-at-uswest-dot-net>
>
> At 11:35 AM 7/27/00 +0200, you wrote:
> >----- Original Message -----
> >From: "Tesla list" <tesla-at-pupman-dot-com>
> >To: <tesla-at-pupman-dot-com>
> >Sent: Thursday, July 27, 2000 2:51 AM
> >Subject: Re: Voltage determination
> >
> >
> >> Original poster: Terry Fritz <twftesla-at-uswest-dot-net>
> >>
> >> Hi Tom,
> >>
> >> The "Vs = Vp sqrt(Ls/Lp)" is a very standard Tesla coil equation.
> >> Personally, I divide the Vs voltage by 1/2 to allow for the source and
> >load
> >> impedance of a real coil.  Thus, I use:
> >>
> >> Vs = 1/2 Vp SQRT(Ls/Lp)
> >>
> >> This is really fairly close in most coils (Vs is a peak voltage).
> >However,
> >> your coil would still be 2.5 million volts which still seems too high!
> >> What are Vp, Ls, and Lp for your coil?
> >>
> >> Cheers,
> >>
> >> Terry
> >
> >Vp is 7300 V,Ls is 30 mH and Lp is 39 µH.My cap is a MMC with 15 nF
> >
>
> Vp = 7300
> Ls = 0.030
> Lp = 0.000039
> sqrt(Ls/Lp) = 27.735
> Vp x 27.735 = 202466
>
> So "I" get 202kV, not 5 million volts!?!  Using my 1/2 rule that would be
> 101kV.  Much more beliveable numbers.
>
> Terry

Oh sorry.My fault !

>
> >>
> >> At 09:34 AM 7/26/00 +0200, you wrote:
> >> >John
> >> >When I take your formula,I have over 5 million Volt.A little much for
a
> >> >6"x25" secondary,don't you think ?
> >> >
> >> >Tom
>
>