Re: NST Inductance

• To: tesla-at-pupman-dot-com
• Subject: Re: NST Inductance
• From: NickandSim-at-aol-dot-com (by way of Terry Fritz <twftesla-at-uswest-dot-net>)
• Date: Mon, 03 Jan 2000 11:33:58 -0700
• Approved: twftesla-at-uswest-dot-net
• Delivered-To: fixup-tesla-at-pupman-dot-com-at-fixme

Hi Ralph,
              calculate it.  The 6/60 neon I have under the bench here has 
maybe 5 or 6K of genuine DC resistance between the output lugs.  However its 
impeadance at the operating frequency is about 100K - this leaves a fair 
amount of impeadance to be accounted for.  The formula for finding the 
components of an impeadance is:

  Z^2 - R^2 = sqrt(wL)

so for our 6/60 nst this is:

  100000^2 - 5000^2 = sqrt(wL)

  10000000000 - 2500000 = 99875

We assume that your're running 50 cycles mains

  99875/314.15 = 318H

I would say you're gonna over run on a 20H meter.

A US nst will have about 83% the inductance of a european nst beacause of the 
higher operating frequency.

Regards
Nick Field

• Prev: Re: SPDT Snon-rotarySG
• Next: Re: Tesla's Energy Trans/dynamo failure
• Index(es):
  • Main
  • Thread