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Re: capacitor
C = 8.84 pF/m * area (in sq m) / spacing (in meters) * relative dielectric
constant
So.. 8.84 * 0.25 m/ .004m = 550 pF (if the dielectric were a vacuum)
Window glass varies widely, but using 4 for the dielectric constant won't
be far off, so the cap would be about 2200 pF (2.2 nF)
Of more concern would be the very lossy characteristics of most window
glass, which means that your glass will get hot, and probably wind up
cracking.
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> From: Tesla List <tesla-at-pupman-dot-com>
> To: tesla-at-pupman-dot-com
> Subject: capacitor
> Date: Sunday, January 02, 2000 2:41 PM
>
> Original Poster: Thomas Gstrein <thomas.gstrein-at-stwimst.at>
>
> I've got two 0,5 m^2 copper plates and window glas in between (0,4cm =
> 4mm). How big is this cap?
>
> greets
> Tom
>
> Tesla List schrieb:
> >
> > Original Poster: Parpp807-at-aol-dot-com
> >
> > In a message dated 1/1/00 9:23:45 PM Central Standard Time,
tesla-at-pupman-dot-com
> > writes:
> >
> > << Hello. How can I calculate a capacitor?
> > >>
> > Hi,
> >
> > Please clarify your question. Just what parameter(s) do you want to
> calculate?
> >
> > Cheers,
> > Ralph Zekelman
>
>