Re: #34 SSE bipolar Coil

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Barton B. Anderson by way of Terry Fritz <twftesla-at-uswest-dot-net>" <tesla123-at-pacbell-dot-net>

Hi Fox,

3.67 lbs. is right on the money. (JavaTC uses the following calc and
indicates 3.67 lbs).

Weight = Wire Length / (1 / ((((Bare Wire Diam. / 2)^2) * pi * 3.853790614))

This is for round copper magnet wire. There will be some error depending on
insulation build and
natural wire tolerances, so always order a bit more than you calc.

Bart

Tesla list wrote:

> Original poster: "Matt Skidmore by way of Terry Fritz
<twftesla-at-uswest-dot-net>" <fox-at-woozle-dot-org>
>
> > http://www.wiretron-dot-com/
>
> they have a nice program on that page that will help calculate
> weight to length for determining how heavy of a spool you'll need. also
> has numerous other features. i found the just the weight calculation
> helpful. 24 awg 3000 ft at about 3.67 pounds, does that sound right?
>
> -fox