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Re: Math Doodling
David -
Your equation Vo = Iin * sqrt(Ls/Cp) was of interest to me because it is
a similar equation to what I show in my Tesla Coil Notebook. In the book it
is shown as Is = Vs sqrt(Cs/Ls).
I also mentioned that this is a form of Ohm's Law. I = V/Z where Z is
the surge impedance sqrt(Ls/Cs).
I am confused by what you mean by "This is RMS tank current etc.". Does
this mean you are combining RMS and Instantaneous equations? Could you
explain this in more detail?
Also, it is my understanding that the tank capacitor should be large
enough to contain all of the available energy. This appears to be contrary
to your belief that the capacitor should be made smaller to leverage energy
by the use of very high voltages??
John Couture
------------------------
-----Original Message-----
From: Tesla List <tesla-at-pupman-dot-com>
To: tesla-at-pupman-dot-com <tesla-at-pupman-dot-com>
Date: Thursday, June 10, 1999 1:57 AM
Subject: Math Doodling
>Original Poster: David Sharpe <sccr4us-at-erols-dot-com>
>
>Terry, ALL
>
>I've been doing some doodling, and off-line discussion with
>Terry, Barry Benson, and John Freau. Here is an interesting
>math derivation to try over a cup of coffee...
>--------------------------------------
>
>Here is a simple math analysis situation that blew Richard Hull
>and Alex Tajnsek away. Based on equations in the Heise paper and
>assuming lossless transfer of power:
>
>Vo = Vin * sqrt ( Ls/Lp ) Where Vo = max Vout from resonator
> Vin = Vin applied to tank circ.
> Ls = Inductance of resonator
> Lp = Inductance of tank pri.
>
>If the following equation is assumed to be correct in the time domain:
>
>Vin = Iin * sqrt ( Lp/Cp ) Where Vin = Vin applied to tank circ.
> Iin = peak tank current
> Lp = Inductance of tank pri.
> Cp = Capacitance of tank C
>
>AUTHORS NOTE: This is RMS tank current times Surge Impedance equals
> applied voltage to tank circuit.
>
>Then substituting equation 2 into 1 and simplifying results in:
>
>Vo = Iin * sqrt ( Ls/Cp ) Variables as listed above
>
>This suggests that Cp should be made a small as possible, and
>to maximize Vo, as high a Vin as possible should be employed. This
>makes sense because Iin will go up with higher Vin, and bang energy is
>.5*C*V^2.
>
>Also, if C is made smaller, dielectric losses maybe REDUCED, with a
>given capacitor (since dielectric area and volume are reduced).
>This is the first time that in doodling with the equations, a
>possible mathematical validation of what has been touted by the TCBOR
>all along is derived, make tank capacitors small, and leverage energy
>by the use of very high voltages.
>
>FYI and discussion. Am I full of it or does this make sense???
>
>Regards
>
>DAVE SHARPE, TCBOR
>Chesterfield, VA. USA.
>
>
>