Re: Caps in series

-----Ursprüngliche Nachricht-----
Von: Tesla List <tesla-at-pupman-dot-com>
An: <tesla-at-pupman-dot-com>
Gesendet: Freitag, 2. Juli 1999 00:42
Betreff: Re: Caps in series

> Original Poster: Grayson B Dietrich <electrofire-at-juno-dot-com>
> Total series capacitance is:
> 1/Ct=(1/C1)+(1/C2)+(1/C3)...+(1/Cn)
> Ct=totla capacitance
> C1...n=each individual capacitance
> -The Electrophile-
> Grayson Dietrich
> Medina, OH
> See my HV Haven (it does NOT do jusctice!)
> www.geocities-dot-com/WestHollywood/Stonewall/2509/index.html
> On Wed, 30 Jun 1999 22:20:13 -0600 Tesla List <tesla-at-pupman-dot-com> writes:
> >Original Poster: Erthwin-at-aol-dot-com
> >
> >I know that if I wire two 5Kv .01uF capacitors in series I'll end up
> >with a
> >10Kv .005uF cap but what happens when I put in a third capacitor that
> >has the
> >same ratings? does the uF rating drop by half again (15Kv .0025) or is
> >it 1/3
> >of the original rating now (15Kv .00333~)...or is there a completely
> >different set of equations for finding this out? I ask this because
> >I'm
> >planning on looking for some smaller voltage caps to wire in series
> >and from
> >the other visits I've made to my local surplus I doubt I'll find
> >anything
> >close to what I actually need so I might end up wiring a LOT of caps
> >in
> >parallel and in series to get the values I'm looking for.
> >
> >Left, left I hadda good brain but it left...
> >---Daniel
> >
> >
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> Hi Daniel,

you are correct with 1/3 of 0.01 uF.
If you wire capacitors in series the total value is 1/(1/C1 + 1/C2+1/C3 ..).

If you wire them in parallel the value is C1+C2+C3.

So if you want to get a special value you must wire several capacitors in
series and parallel, its a little puzzle.