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Re: Limiting Safety Gap Current
Um, um,,,,
> Original Poster: "Marco Denicolai" <Marco.Denicolai-at-tellabs.fi>
<snip>
> An inductive load dissipates energy only in its resistive losses!
> Again, an ideal inductance DELAYS the current rising but allows it anyway
> to rise as much as it could without the inductance.
If CV^2 is constant and you increase L, what happens to I? Another
way of looking at it is I = V*SQRT(C/L)
> A resistor IMHO is the right solution.
I think so too.
Malcolm