Re: Re: DC behavior with AC TC

To: tesla-at-pupman-dot-com
Subject: Re: Re: DC behavior with AC TC
From: "John H. Couture" <COUTUREJH-at-worldnet.att-dot-net> (by way of Terry Fritz <twf-at-verinet-dot-com>)
Date: Thu, 31 Dec 1998 18:37:53 -0700
Approved: twf-at-verinet-dot-com

  Robert -

  Thank you for correcting my statement. I had forgotten that the VdG
terminal could be positive by removing electrons from the terminal. The work
(energy) would be

  Joules = Q x V

  Can this equation be related to the motor to show that the belt motor
would slow down as the voltage builds up on the terminal? The charge would
be zero on the inside of the terminal. 

  John Couture

-----------------------------

At 12:02 PM 12/29/98 -0700, you wrote:
>Original Poster: KRAMPF-at-aol-dot-com 
>
>
>In a message dated 12/28/98 6:16:17 PM, John Couture wrote:
>
><<The Van de Graaff terminal is always negative. >>
>
>John, depending on its design, a Van de Graaff can be either negative or
>positive. Wabash Instruments sells them in both configurations and a matched
>set gives quite a spark!  
>
>Robert Krampf
>Science Education Company
>http://members.aol-dot-com/krampf/home.html
>Get my Free Experiment of the Week by sending an e-mail to krampf-at-aol-dot-com
>
>
>