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capacitor energy vs pwr factor
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From: Malcolm Watts [SMTP:MALCOLM-at-directorate.wnp.ac.nz]
Sent: Wednesday, February 11, 1998 5:10 PM
To: Tesla List
Subject: Re: capacitor energy vs pwr factor
Hi Bill,
> From: Wysock, William C. [SMTP:Wysock-at-courier8.aero-dot-org]
> Sent: Tuesday, February 10, 1998 12:57 PM
> To: Tesla List
> Cc: ttr
> Subject: RE: capacitor energy vs pwr factor
>
>
> To all working with NST's as a power source.
>
> With any NST (containing a magnetic leakage shunt in its core;
> whether it be "stock" or "modified" for higher current) and
> irrespective of using external a.c. electrolytic power factor
> correction capacitors, there seems to be something
> fundamental missing in everyone's calculations. Remember,
> you can hard-wire short the secondary terminals on an NST
> without burning the thing up. If your NST was rated for example,
> at 60 ma., you will have 60 ma. flowing in the short circuit. BUT,
> you will have "0" volts. The voltage output of an NST is
> inversely proportional to the amount of current being drawn.
> The only time you have say, 15 KV rms at the output terminals
> is when NO current is being drawn. The bottom line is that
> at no point do you have 15 KV *and* 60 ma., at the same time.
I think that only applies to a resistive load. I've seen a
transformer ringing up with a capacitive load. I've seen Q's in the
vicinity of 6 at mains frequency with one combination I checked.
?
Malcolm
> The load voltage and current will be less (for the point where
> the current sine wave phase angle crosses the voltage sine
> wave phase angle,) to yield maximum usable power.
>
> Bill Wysock
> -------------------------------------------
> Tesla Technology Research
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