[Prev][Next][Index][Thread]

RE>Re: UK coilers ? + stuff (fwd)



---------- Forwarded message ----------
Date: 03 Aug 1998 14:44:06 -0700
From: Dale Hall <Dale.Hall-at-trw-dot-com>
To: Tesla List <tesla-at-pupman-dot-com>
Subject: RE>Re: UK coilers ? + stuff

RE>Re: UK coilers ? + stuff (fwd)

Chris & Al,

I agree with  Al's good comments, except,

I disagree regarding the uA output current of a TC, seems he was talking
average where it the peak values that need to be considered (or perhaps
he is referring to overall corona current with no concentrated spark ?)
Sparks and corona represent impulse events necessitating peak terminology.
Wire ratings are for heating values (cross section area). 
Surface area & skin affect at relevant tesla frequencies determine peak
current  capability. The pulse repetitiion rate never gets high enough to
become a wire heating restriction.  

In my battery powered DC TC, 12v .04A to  5kVDC,  .1uF, .125" ~4turn pri,
 6.25"x20" sec #24 ~20mHy,  8"x20" toroid, 8" to 10" sparks:

Ipri ~ 600 A pk measured with a Tektronix current probe (220kHz).

Isec ~22 A pk measured spark return line current (~2 to 20mHz)

Dale  Redondo Beach, Calif

------------------------------
Date: 8/1/98 8:45 PM
To: Hall, Dale
From: List, Tesla

Date: Sat, 1 Aug 1998 17:04:53 EDT
From: Alfred A Skrocki <alfred.skrocki.sr-at-juno-dot-com>
Subject: Re: UK coilers ? + stuff (fwd)

On Fri, 31 Jul 1998 18:37:50 +0100 Chris Swinson
<chris.swinson-at-zetnet.co.uk> wrote;

snip.....
>what's the output current of a coil ?  I know the capacitor may well 
>give a very small peek of up to 1000's of amps, But the current rating
of the
>wire in my secondary is about 140 ma, Does this mean I can only draw 
>140ma or is there something else to it all. 

Typically the current output of a coil like yours is in the micro-amp
range.
The current out put is in accordance with the conservation of energy
rule. ie the power input is the same as the power output (minus losses of
course) so since the voltage output is soo much higher than the voltage
input the output current must be accordingly much smaller.

>snip
                               Alfred A. Skrocki
                          Alfred.Skrocki.Sr-at-JUNO-dot-com