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Re: A Puzzle
From: Richard Wayne Wall[SMTP:rwall-at-ix-dot-netcom-dot-com]
Sent: Sunday, September 07, 1997 9:39 AM
To: Tesla List
Subject: Re: A Puzzle
9/7/97
Dr. R wrote:
>> >The peak current in amps can easily be determined by measuring the
>> >total capacitance of the machine. Divide the in coulombs by the
>> >time in sec (assume 1 microsec for most machines) and this gives
>> >the total peak current in amperes.
>Theory or not withstanding, it has come to within 2% of actual
>measured value and that works well enough for our purposes. For
>exacting research work, I agree, it is not accurate enough.
No one can deny that a Van de Graf generator is an electrostatic device
that collects electrostatic energy on its terminal. Your initial
comment indicates a derived EM current using Coulombs from an
electrostatic device. Now you indicate this derived value is within 2%
of a measured value.
There is a several order of magnitude error in the experimental
comparison of EM vs ES Coulombic forces. Not a 2% error, nor exacting
research work.
This calls into question your method of measuring current in an air
discharge of a Van de Graf generator.
RWW