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Re: A "Revolutionary" Idea
Subject:
Re: A "Revolutionary" Idea
Date:
Sat, 22 Mar 1997 12:59:23 -0800
From:
Bert Hickman <bert.hickman-at-aquila-dot-com>
Organization:
Stoneridge Engineering
To:
Tesla List <tesla-at-pupman-dot-com>
References:
1
Tesla List wrote:
>
> Subject:
> A "Revolutionary" Idea
> Date:
> Fri, 21 Mar 1997 13:27:05 GMT
> From:
> Joe Cummings <joecmn-at-globalnet.co.uk>
> To:
> tesla-at-pupman-dot-com
>
> At present I'm not able to do any practical work, so all I do is carry
> out
> Gedankenforschungen - thought experiments.
>
> I have an idea about rotary spark gaps that, knowing the amount of
> expertise
> to be found on this list, I'm sure has been dealt with before. Anyway,
> I'll
> float it.
>
> I assume a rotary S.G. has an electrode on the rotor, which, as it
> rotates
> comes opposite one or more electrodes on the stator, so to get more
> frequent
> sparks, the rotor has to be accelerated.
>
> Now, has anyone tried staggering a number of electrodes on the rotor, so
> that there
>
> is more than one spark per rev, or x sparks per rev, depending on the
> number of electrodes on the stator?
>
> Let's build a rotary with six static electrodes, and five on the rotor.
> Let
> us space the electrodes on the rotor using a compass, set, not at the
> radius, but at the length of the radius plus one fifth the length of the
> radius. Let's call the stator elctrodes S1,S2,etc., and the rotary
> electrodes R1,R2,etc.
>
> Now starting with R1 and S1 sparking opposite each other, after a fifth
> times a sixth of a revolution, R2 and S2 are sparking, and after another
> thirtieth of a rev., R3 and S3 are sparking and so on. This will mean
> that
> there are thirty sparks per revolution.
>
> Is this a feasible proposition? If so, then it could be worked out for
> any
> number of
> electrodes.
Joe,
Slight modification to the post I sent before - the assumption is that
you will never have more than one pair of electrodes in a position to
fire at the same time. If you had M=6 and N=6 and all were equally
spaced, the NxM equation does not hold - you'd obviously get just 6
breaks/revolution. As long as M and N are not factors of one another and
are not the same, the relationship should hold.
-- Bert H --