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Re: Tesla turns ratio ?
Subject: Re: Tesla turns ratio ?
Date: Sat, 14 Jun 1997 17:05:01 -0600
From: "DR.RESONANCE" <DR.RESONANCE-at-next-wave-dot-net>
To: "Tesla List" <tesla-at-pupman-dot-com>
To: Owen Lawrence
As you pointed out the energy in the primary is transferred to the sec.
coil minus the normal losses. Also as you noted, according to classical
physics texts this would imply a rather small terminal capacitance. In
the
real world it seems the larger the terminal capacitance the better for
maximum voltage output. This assumes of course that you have a very
large
amount of primary capacitance and a suitable means to quickly recharge
this
cap.
With regards to your question on max energy and efficiency you might
wish
to look up the two following articles and study them in detail.
A Radio-Frequency High Voltage Generator
D.H. Sloan Physical Review vol 47 Jan. 1, 1935 pp.62-70
Sloans proclaims efficiencies of only 50% or less with the classic
coupled
tuned circuit coil system and then he goes on to discuss (and develops)
the
tightly tuned circuit in a wave guide like tank system. His ultra hi-Q
vacuum tube oscillator runs at 150 kw and develops over 1,000,000 volts
with only a 15 kv input into a single magnifier-type helical coil with
only
18 total turns! This resonance transformer system is tightly coupled
and
runs very high efficiencies of around 90-95%.
Another great article was published by Dr. James and Dr. Kenneth Corum
entitled:
A Technical Analysis of the Extra Coil as a Slow Wave Helical
Resonator
available thru the International Tesla Society Proceedings in
Col. Springs
Both Jim and Ken studied Sloan's work in detail and offer an in depth
technical analysis.
More good information is givin in Electrical Condensers
Philip Coursey Pitman & Sons London
1927
Hope this information is of assistance.
DR.RESONANCE-at-next-wave-dot-net
----------
> Subject: Re: Tesla turns ratio ?
> Date: Fri, 13 Jun 1997 00:11:11 -0400
> From: "Owen Lawrence" <owen-at-iosphere-dot-net>
> To: "Tesla List" <tesla-at-pupman-dot-com>
>
>
> > related to the ratio of primary to secondary turns! For the benefit
> > of anyone who is not familiar with the derevation of the ratio of
> > trasformation in a Tesla coil here it is:
> >
> > E = .5 x C x V^2 :energy stored in a capacitor
> > Eprimary = Esecondary :conservation of energy law
> >
> > combining the two equations gives;
> >
> > .5 x Cprimary x Vprimary^2 = .5 x Csecondary x Vsecondary^2
> >
> > dividing both sides by .5 gives;
> >
> > Cprimary x Vprimary^2 = Csecondary x Vsecondary^2
> >
> > Solving in terms of Vsecondary gives;
> >
> > Vsecondary = SQRT (Cprimary / Csecondary)
>
> Thank you for your very clear explanation. However, if CpVp^2 = CsVs^2,
> then Vs = VpSQRT(Cp/Cs).
>
> > Realize this is a theoretical maximum and many factors effect it such
> > as resistive losses, dialectric losses, coronal leakage, ect.
> > Examining the above equations should clearly show that ones goals are
> > to make the secondary capacitance as small as possible while at the
>
> Looking at these equations, it can't hurt to start out with a higher
> primary voltage, either. With a Cp to Cs ratio of 10000 every kilovolt
> increase of input is another hundred kilovolts of output
> (theoretically).
>
> > small as is practical. I say practical because a one turn wide
> > diaeter primary may give minimum inductance but it may not transfer
> > all the primary energy to the secondary and using too large a primary
>
> Now you've gone and said too much, because you make me think of a whole
> bunch of questions: How much power can theoretically be transferred to
> the
> secondary? Can someone please explain exactly how the transfer takes
> place, anyway? With the large currents in the primary coil there is a
> big
> magnetic field. This will induce currents in the secondary. But there
> is
> also a large electric field about the primary conductor, too, isn't
> there?
> How does it affect the currents in the secondary? Does the energy
> driving
> the secondary arrive like radio waves to the antenna of my TV (which
> means
> exactly WHAT? by the way) or does it arrive like a moving magnet next to
> a
> charge? Since these fields must be spreading out from the primary coil
> away from the secondary, I assume power is lost. Is there any way to
> shape
> the fields in such a way as to focus them on the secondary coil
> "target"?
>
> Thanks for any and all responses.
>
> - Owen -