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RE: Another formula to throw on the fire (fwd)
---------- Forwarded message ----------
Date: Mon, 15 Dec 1997 09:11:20 -0500
From: "Thornton, Russ #CSR2000" <ThorntoR-at-rc.pafb.af.mil>
To: 'Tesla discussion Group' <tesla-at-pupman-dot-com>
Subject: RE: Another formula to throw on the fire
BTW, in the Q.E.D. Should it not be:
L=piN(Ro+Ri) [Q.E.D.],[Q.E.D.]
Russ Thornton
CSR 2040,
Building 989, Rm. A1-N20
Phone: (407) 494-6430
Email: thorntor-at-rc.pafb.af.mil
>----------
>From: Tesla List[SMTP:tesla-at-pupman-dot-com]
>Sent: Friday, December 12, 1997 10:13 AM
>To: 'Tesla List'
>Subject: Re: Another formula to throw on the fire
>
>
>From: D.C. Cox[SMTP:DR.RESONANCE-at-next-wave-dot-net]
>Sent: Thursday, December 11, 1997 6:57 PM
>To: Tesla List
>Subject: Re: Another formula to throw on the fire
>
>to: Adam
>
>Great idea! It's an equation I have never seen in print before. One
>question: Is the radius measured from the center of the circle?? Not sure
>what you mean by center of the tubing?
>
>DR.RESONANCE-at-next-wave-dot-net
>
>
>----------
>> From: Tesla List <tesla-at-pupman-dot-com>
>> To: 'Tesla List' <tesla-at-poodle.pupman-dot-com>
>> Subject: Another formula to throw on the fire
>> Date: Thursday, December 11, 1997 8:13 AM
>>
>>
>> From: Adam[SMTP:absmith-at-tiac-dot-net]
>> Sent: Wednesday, December 10, 1997 9:57 PM
>> To: tesla list
>> Subject: Another formula to throw on the fire
>>
>>
>> I computed a simple integration for finding out how much tubing or wire
>> is need for a primary coil that may be of use to those building coils.
>> The formula is as follows:
>>
>> For a flat (or slightly banked) spiral primary coil of:
>>
>> Inside (starting) radius Ri
>> Outside (final) radius of Ro (Both Radii measured from the center of
>
>> the tubing)
>> N number of turns
>>
>> The total length of wire/tubing (L) required is: pi * N * (Ro + Ri)
>> Pretty simple end result, eh? Independent of units chosen too, as long
>> as you are consistant of course!
>>
>>
>> ---------------------------
>> For completeness, here is my entire calculation:
>>
>> The integrand was radius as a function of Theta:
>>
>> R = (W/2pi) * (Ro - Ri)/N + Ri where W is Theta in Radians
>>
>> Integrating the radius this over all 2*pi*N turns (henceforth 2piN) we
>> get L:
>>
>> _ (2piN)
>> /
>> L = / [(W/2pi)(Ro - Ri)/N + Ri] dW
>> _/
>> 0
>>
>>
>> L = [(Ro - Ri)/2piN] * [(2piN)^2/2] + 2piN*Ri
>>
>>
>> L = piN(Ro-Ri) + 2piN*Ri
>>
>>
>> L = piN(Ro-Ri) [Q.E.D.]
>>
>> -Adam
>>
>>
>>
>--------------------------------------------------------------------------
>> Adam Smith
>> absmith-at-tiac-dot-net
>> Epoch, Inc. Digital Music Project
>>
>> www.tiac-dot-net/users/absmith/ MP3 Demo Tracks Now
>Available!
>>
>--------------------------------------------------------------------------
>>
>>
>>
>
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