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Re: Real data from real experiments.

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Hi Group,
I think the question I posed, way back when, shows the clear conflict
between theory and reality. If the question is taken as theoretical then no
clear answer can be found since an infinite current would have to flow
between the two capacitors. Remember in theory there was no resistance or
inductance included in the original question and therefore no oscillation
would occur, damped or otherwise. So maybe in theory the final voltage
across the caps would be 0.707V.
In reality there is always resistance and inductance in a circuit and the
capacitors will always end up with 50% of the energy, most of the rest of
the energy goes to heat after the oscillations have gone. 
In theory there can be a free lunch, in reality you have to pay. This one
has been beaten to a bloody pulp.

Dave Huffman

[ I agree!! -- Chip]
> > Subject: Re: Real data from real experiments.
> 
> From bturner-at-apc-dot-netTue Nov 12 22:39:18 1996
> Date: Tue, 12 Nov 1996 12:49:55 -0800
> From: open_minded <bturner-at-apc-dot-net>
> To: tesla-at-pupman-dot-com
> Subject: Re: Real data from real experiments.
> 
> Tesla List wrote:
> > 
> > >From MALCOLM-at-directorate.wnp.ac.nzMon Nov 11 22:51:02 1996
> > Date: Tue, 12 Nov 1996 08:31:39 +1200
> > From: Malcolm Watts <MALCOLM-at-directorate.wnp.ac.nz>
> > To: tesla-at-pupman-dot-com
> > Subject: Re: Real data from real experiments.
> > 
> > >   Exactly...  Actually, I mentioned the hydraulic analogy
> > > to Jack a while back, with no better comprehension resulting.
> > > I suggested comparing the two caps to two water tanks, one
> > > filled, the other, identical tank empty. Open a valve that
> > > connects the two at the bottom. After oscillating a bit,
> > > the water levels end up at 1/2 the original height, and
> > > a total of 1/2 the original POTENTIAL energy is available.
> > > Certainly, nothing was "radiated", and we can't easily
> > > believe the water was heated that much by friction as it
> > > passed through the valve and pipes.
> > >
> > 
> > C'mon guys. If the system oscillates, you have kinetic energy in
> > there. When it stops, you have lost the kinetic energy. This is
> > physics 1.
> > 
> > Malcolm
> 
> 
> Well, yeah. But I was talking in the ideal situation. I can't believe
> that more than, say 5 or 10% of the charge is 'written off' to losses,
> unless you are really pumping a load of current through the wire. At
> least the losses shouldn't come close to 1/2 of the total original
> energy. The idea of this thread was on a theoretical basis anyway.
> 
> - brent