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Re: TC Electrostatics (fwd)
Tesla List wrote:
>
> >From chip-at-poodle.pupman-dot-com Mon Dec 2 22:33:45 1996
> Date: Mon, 2 Dec 1996 21:47:41 -0700 (MST)
> From: Chip Atkinson <chip-at-poodle.pupman-dot-com>
> To: Tesla List <tesla-at-poodle.pupman-dot-com>
> Subject: Re: TC Electrostatics (fwd)
>
> ---------- Forwarded message ----------
> Date: Mon, 02 Dec 1996 08:20:26 -0500
> From: Dan Kline <ntesla1-at-vishnu.csd.sc.edu>
> To: chip-at-pupman-dot-com
> Subject: Re: TC Electrostatics
>
> >From: huffman <huffman-at-fnal.gov>
> >To: tesla-at-pupman-dot-com
> >Subject: Re: TC Electrostatics
> >
> >I saw an interesting thing while firing my coil on the work bench. An
> >article from a magazine was hanging from a hook about 20" from the
> >discharge electrode. When the coil was operated the paper pulled itself to
> >the pegboard clearly do to electrostatic charge. It's amazing how much
> >static these things put out.
> >Dave
>
> and
>
> [snip]
> >There's also
> >strong empirical evidence that disruptive (but not CW) coils
> >electrostatically "charge up" operators in a similar fashion, so there
> >also appears to be some interaction(s) associated with the higher peaks,
> >relatively low duty cycle, or damped wavetrains. But just how does this
> >all fit together?? This is really interesting stuff!!
> >
> >BTW, could you determine if the plate became positively or negatively
> >charged?
> >
> >-- Bert --
>
> My guess would be that plate was positively charged.
>
> Could it be like this:
>
> Let's say that we are going to fire a coil one time, say 1 "pulse", and the
> coil will ring down in 5 complete cycles. Let's also say that the first
> half-cycle, i.e. the first and highest voltage rise, will be positive in
> nature. In other words, the ionic output at the secondary's terminal will be
> positive. This is only for the first half-cycle.
>
> The following half-cycle, will be negative, i.e. the ionic output will be
> negative.
>
> The total cycle above will equal one "ring."
>
> The next half-cycle will be positve, the next following half-cycle will be
> negative, and so on until all five cycles have been completed, and the coil
> has completely rung down.
>
> >From what I *pretend* to understand ;) positive ions lack electrons, and
> negative ions have a surplus of electrons. In that case, in the first
> half-cycle, the positive ions would be accelerated farther away from the
> secondary's terminal than the following, heavier, and less-accelerated
> negative ions during their next half-cycle. This would be on the first
> completed cycle.
>
> On the beginning of the next ring, the positive half-cycle would accelerate
> the lighter, positive ions to about where the heavier negative ions had
> stopped, neutralizing most of them. Then the succeeding negative half-cycle
> would throw out more negative ions, heavy, and way less-accelerated, only to
> be neutralized by the lighter positives on the next cycle. (I suppose the
> positives could be accelerated *past* the negatives, but it really doesn't
> matter for this analogy.) The process would continue until the coil had
> completely rung down, leaving a cloud of positive ions far away from the
> secondary's terminal, relatively speaking.
>
> If we were to have successive wave-train of five-ring-pulses, (forgive me if
> I'm mixing terms ;) then the positive ion-cloud at the far reaches of the
> "coil-space" would continue to increase in size simply because the lighter
> ions would propelled farther than the would-be-neutralizing negative ions.
>
> 5 cycles
>
> + - + - + - + - + ________________
> + + - + - + - + - + (____terminal____)
> + - + - + - + - + | |
> | |
>
> 5 more cycles
>
> + + + - + - + - + - + ________________
> + + + - + - + - + - + (____terminal____)
> + + + - + - + - + - + | |
> | |
>
> ...and 5 *more* cycles
>
> + + + + +
> + + + + + + - + - + - + - + ________________
> + + + + + - + - + - + - + (____terminal____)
> + + + + + + - + - + - + - + | |
> + + + + + | |
>
> Something like that. :)
>
> Of course, this is all just speculation, I'm no scientist. *laugh*
> But I do think that the ions will be accelerated to a point where the
> heavier negatives can't catch up. I'm also not sure about how to make the
> first cycle positive...maybe power-supply phasing? On the other hand, it
> could be that free electrons are being accelerated, since they're the
> lightest of all. I'd be way interested in finding out what the usual
> polarity-of-charge ends up being.
>
> Just thinking out loud,
>
> Dan
Dan,
I have published several scenarios similar to the one you depict above
and it is most likely the causitive agent in this process. You neglected
coulombic acceleration from the discharger and the resulting failure to
sweep up all the original ions. Furthermore, one charge polarity
mechanism might prove to be more efficient than another.
The charging and acceleration by coulombic forces would be greatest with
a point attached to a massive terminal load. (which is what we have seen
and verified.) In addition, The pulses in the ring cycle are diminishing
in amplitude with time. It would stand to reason that the first pulse,
where most of the energy of the cap is expended, would determine the
charge polarity. This has yet to be definitively shown, but will be
thoroughly tested out in the near future. Look for my Tesla
electrostatics article in an upcoming TCBA NEWS.
Richard Hull, TCBOR