Re: changing dielectrics in a capacitor (fwd)

[Steven Roys <sroys@xxxxxxxx>]

---------- Forwarded message ----------
Date: Mon, 19 Jan 2004 22:53:15 +0200
From: gtyler <gtyler@xxxxxxxxxxxxxxx>
To: High Voltage list <hvlist@xxxxxxxxxx>
Subject: Re: changing dielectrics in a capacitor (fwd)

Very interesting! It must, to keep the maths correct.

George Tyler

----- Original Message -----
From: "High Voltage list" <hvlist@xxxxxxxxxx>
To: <hvlist@xxxxxxxxxx>
Sent: Monday, January 19, 2004 8:01 PM
Subject: changing dielectrics in a capacitor (fwd)


> Original poster: Steven Roys <sroys@xxxxxxxx>
>
>
>
> ---------- Forwarded message ----------
> Date: Sun, 18 Jan 2004 23:01:41 -0500
> From: Alfred Erpel <alfred@xxxxxxxxx>
> To: High Voltage list <hvlist@xxxxxxxxxx>
> Subject: changing dielectrics in a capacitor
>
>
>
> Howdy all,
>
>     Imagine a parallel plate capacitor where all metal plates of the
> capacitor are fixed, and you can rotate the dielectric material with a
k=10
> from full coverage between the metal plates to no coverage where the
new
> dielectric is air k=1.
>
>     Lets say we start with the air as dielectric and the capacitor is
rated
> at .001µF and charged to 10,000 volts.
>
>     When the k=10 dielectric material is rotated totally into place to
> replace the k=1 air, what happens?
>
> I will speculate:
>
> Q=C*V wants to stay the same so as the capacitance increases to .01µF
the
> voltage drops to 1000 volts.
>
> The capacitor now has 1/10 of its original energy.  If my speculations
are
> correct, what happened to the 9/10 of the energy that went away?  Does
the
> new dielectric want to get "sucked" in?
>
> Regards,
> Al Erpel
>
>
>