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Re: Beginner : Joules to amperage
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- Subject: Re: Beginner : Joules to amperage
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Sat, 09 Jul 2005 14:31:29 -0600
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Original poster: Terry Fritz <teslalist@xxxxxxxxxxxxxxxxxxxxxxx>
Hi,
At 12:10 PM 7/9/2005, you wrote:
Hello
I have a capacitor that is rated 80mfd at 1300 Vac. I
calculated 676 joules.
E = 1/2 x C x V^2 == 1/2 x 80e-6 x 1300^2 = 67.6 joules
I need to know the amps per
discharge. Is there any way to do that?
It is the voltage (1300) divided buy the resistance or impedance of the
load. If it is 100 ohms:
I = V / R == 1300 / 100 = 13 amps
If the load is an inductor:
Z = SQRT(L / C)
I = V / Z
So if the inductor is 100uH:
Z = SQRT(100e-6 / 80e-6) = 1.11 ohms
I = 1300 / 1.11 = 1163 amps
Things can get for more complex depending on what you have there...
Cheers,
Terry