[Prev][Next][Index][Thread]
Re: Toroid Design .
DC -
I was referring to the belt motor. Does the belt motor slow down as the
voltage increases on the terminal?
John Couture
-------------------------------
At 08:56 AM 12/30/98 -0700, you wrote:
>Original Poster: "D.C. Cox" <DR.RESONANCE-at-next-wave-dot-net>
>
>to: John
>
>The pelletron type Van de Graaffs built by National Electrostatics function
>as excellent HV DC motors when the units are turned off. They will run for
>over 60 seconds on the stored charged.
>
>----------
>> From: Tesla List <tesla-at-pupman-dot-com>
>> To: tesla-at-pupman-dot-com
>> Subject: Re: Toroid Design .
>> Date: Tuesday, December 29, 1998 12:03 PM
>>
>> Original Poster: "John H. Couture" <COUTUREJH-at-worldnet.att-dot-net>
>>
>>
>> Ed -
>>
>> Isn't the charge zero on the inside of the upper terminal during VDG
>> operation? How can there be an "up hill" effect for the charge on the
>belt?
>> I would consider it a "down hill" effect.
>>
>> The work to put the charge (100% eff) on the outside of the terminal is
>>
>> W = Q x V joules per coulomb
>>
>> Have you found an equation to relate this work to the motor that would
>> indicate the motor slows down as the voltage on the outside of the
>terminal
>> increases?
>>
>> John Couture
>>
>> --------------------------------------
>>
>> At 08:17 PM 12/25/98 -0700, you wrote:
>> >Original Poster: Ed Phillips <evp-at-pacbell-dot-net>
>> >
>> >" Jim -
>> >
>> > This is the first time I have heard that the Van deGraaf motor slows
>> >down
>> >because of the upper electrode voltage. I thought the transfer of
>> >charges
>> >from the belt to the inside of the sphere was because the potential on
>> >the
>> >inside of the sphere was less than on the belt.
>> >
>> > John Couture"
>> >
>> > The motor slows down (if it is of marginal power, at least) because, as
>> >the upper terminal voltage increases, more work is being done to move
>> >the charges "up hill". Real effect!
>> >
>> >Ed