[Prev][Next][Index][Thread]
Fw: Terry's GM HEI Coil Update
Ed,
I goofed on these two equations. F = 1/(2(pi)RC), and C =
(1/(F/2(pi)R))/5 The coil inductance equations look almost the same, except
everything is being used to divide one with capacitors. I walked away from
my computer, thinking, and remember the equation, and had to come back and
correct myself. I'm sure I would have had time designing it to discover
that before I bought parts..
James.
>
> Coulombs, if his capacitor is bigger than yours in the spark gap, his
>discharge is going to be hotter, and longer. If his supply is at 60 mA,
and
>yours at 30mA, the value of capacitor he needs at the same frequency is
>twice the value. Impedance matching desides when the gap fires. So the
>output impedance = 15Kv/30mA which is 500K ohms, but his output impedance
>is 250k ohms. Therefore F= 2(pi)RC, and for a spark gap C = (F/2(pi)R)/5
>Because capacitor timing equations are based on 63% of their actual charge
>time, and in order to get the maximum spark voltage, and length you cannot
>use a normal frequency calculation. If you were using the Universal Time
>Constant Curve, then you would see how the spark gap could be calculated
>using that equation. If you work the equation for the two resistance
values
>you get to totally different answers, and one is weak compared to the other
>at the spark gap. Therefore, a Bigger capactor stores more electrons, and
>has a higher number of watts out, although, that is pulsed, and in
>microseconds.. So, I guess the better way of asking that question who has
>the highest output over the time period in uS's.
>
>James
>
>
>>Original Poster: Ed Phillips <evp-at-pacbell-dot-net>
>>
>>"Original Poster: "James" <elgersmad-at-email.msn-dot-com>
>>
>> Try checking out the value of capacitor that you were using, and
>>compare
>>it to the value he is using, in watts."
>>
>> What is the conversion factor from watts to farads?????????
>>
>>Ed
>>
>>
>
>