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RE: Another formula to throw on the fire (fwd)





---------- Forwarded message ----------
Date: Mon, 15 Dec 1997 09:11:20 -0500
From: "Thornton, Russ #CSR2000" <ThorntoR-at-rc.pafb.af.mil>
To: 'Tesla discussion Group' <tesla-at-pupman-dot-com>
Subject: RE: Another formula to throw on the fire

BTW, in the Q.E.D.  Should it not be:

L=piN(Ro+Ri)   [Q.E.D.],[Q.E.D.]

Russ Thornton
CSR 2040, 
Building 989, Rm.  A1-N20
Phone: (407) 494-6430 
Email: thorntor-at-rc.pafb.af.mil


>----------
>From: 	Tesla List[SMTP:tesla-at-pupman-dot-com]
>Sent: 	Friday, December 12, 1997 10:13 AM
>To: 	'Tesla List'
>Subject: 	Re: Another formula to throw on the fire
>
>
>From: 	D.C. Cox[SMTP:DR.RESONANCE-at-next-wave-dot-net]
>Sent: 	Thursday, December 11, 1997 6:57 PM
>To: 	Tesla List
>Subject: 	Re: Another formula to throw on the fire
>
>to: Adam
>
>Great idea!  It's an equation I have never seen in print before.  One
>question:  Is the radius measured from the center of the circle??  Not sure
>what you mean by center of the tubing?
>
>DR.RESONANCE-at-next-wave-dot-net
>
>
>----------
>> From: Tesla List <tesla-at-pupman-dot-com>
>> To: 'Tesla List' <tesla-at-poodle.pupman-dot-com>
>> Subject: Another formula to throw on the fire
>> Date: Thursday, December 11, 1997 8:13 AM
>> 
>> 
>> From: 	Adam[SMTP:absmith-at-tiac-dot-net]
>> Sent: 	Wednesday, December 10, 1997 9:57 PM
>> To: 	tesla list
>> Subject: 	Another formula to throw on the fire
>> 
>> 
>> I computed a simple integration for finding out how much tubing or wire 
>> is need for a primary coil that may be of use to those building coils.  
>> The formula is as follows:
>> 
>> For a flat (or slightly banked) spiral primary coil of:
>> 
>>      Inside (starting) radius Ri
>>      Outside (final) radius of Ro (Both Radii measured from the center of
>
>> the tubing) 
>>      N number of turns
>> 
>> The total length of wire/tubing (L) required is:  pi * N * (Ro + Ri) 
>> Pretty simple end result, eh?  Independent of units chosen too, as long 
>> as you are consistant of course!
>> 
>> 
>> ---------------------------
>> For completeness, here is my entire calculation:
>> 
>> The integrand was radius as a function of Theta:
>> 
>> R = (W/2pi) * (Ro - Ri)/N + Ri    where W is Theta in Radians
>> 
>> Integrating the radius this over all 2*pi*N turns (henceforth 2piN) we 
>> get L:
>> 
>>       _ (2piN)
>>      /
>> L = / [(W/2pi)(Ro - Ri)/N + Ri] dW 
>>   _/
>>     0
>> 
>> 
>> L = [(Ro - Ri)/2piN] * [(2piN)^2/2] + 2piN*Ri
>>  
>> 
>> L = piN(Ro-Ri) + 2piN*Ri 
>> 
>> 
>> L = piN(Ro-Ri)    [Q.E.D.]
>> 
>> -Adam
>>      
>> 
>>
>--------------------------------------------------------------------------
>> Adam Smith
>> absmith-at-tiac-dot-net
>> Epoch, Inc. Digital Music Project
>> 
>> www.tiac-dot-net/users/absmith/                 MP3 Demo Tracks Now
>Available!
>>
>--------------------------------------------------------------------------
>> 
>> 
>> 
>
>
>
>